12m^2=3

Solution for 12m^2=3 equation:

12m^2=3

We move all terms to the left:

12m^2-(3)=0

a = 12; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·12·(-3)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12}{2*12}=\frac{-12}{24}
=-1/2
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12}{2*12}=\frac{12}{24}
=1/2
$